Question

1) Resolver as expressões numéricas a seguir: ​

Answer 1

Resposta e explicação passo a passo:

$1-\\\\a)\ \frac{7}{2}\bullet\frac{7}{6}+\frac{(-\frac{7}{2})}{\frac{3}{2}}\\\\\frac{49}{12}+(-\frac{7}{2}\bullet\frac{2}{3})\\\\\frac{49}{12}-\frac{14}{6}=\frac{6(49)+12(-14)}{72}=\frac{294-168}{72}=\frac{126}{72}=\frac{7}{4}=1,75$

$b)\ \frac{7}{\frac{1}{3}}-\frac{(\frac{-5}{3})}{\frac{5}{4}}\\\\7\bullet\frac{3}{1}-(-(\frac{5}{3}\bullet\frac{4}{5}))\\\\21+\frac{20}{15}=\frac{315+20}{15}=\frac{335}{15}=\frac{67}{3}=22,33$

$c)\ \frac{\frac{7}{5}}{\frac{1}{2}}-\frac{5}{4}\bullet3\\\\\frac{7}{5}\bullet\frac{2}{1}-\frac{15}{4}\\\\\frac{14}{5}-\frac{15}{4}=\frac{4(14)-5(15)}{20}=\frac{56-75}{20}=-\frac{19}{20}=0,95$

$d)\ \frac{5}{3}-\frac{\frac{3}{4}}{\frac{1}{4}}\\\\\frac{5}{3}-(\frac{3}{4}\bullet\frac{4}{1})\\\\\frac{5}{3}-\frac{12}{4}\\\\\frac{5}{3}-3=\frac{5+5(-3)}{5}=\frac{5-15}{5}=-\frac{10}{5}=-2$

$e)\ \frac{7}{9}\bullet(-\frac{3}{4})+\frac{(-\frac{7}{5})}{3}\\\\-\frac{21}{36}+(-\frac{7}{5}\bullet\frac{1}{3})\\\\-\frac{7}{12}-\frac{7}{15}=\frac{15(-7)+12(-7)}{180}=\frac{-105-84}{180}=-\frac{189}{180}=-\frac{21}{20}=-1,05$

$f)\ \frac{3}{4}-(-\frac{1}{8})-\frac{7}{3}\bullet(-\frac{3}{9})\\\\\frac{3}{4}+\frac{1}{8}+\frac{21}{27}\\\\\frac{3}{4}+\frac{1}{8}+\frac{7}{9}=\frac{72(3)+36(1)+32(7)}{288}=\frac{216+36+224}{288}=\frac{476}{288}=\frac{119}{72}=1,65$