Question

log9 (2x-5) mudar para base 3

Answer 1

Resposta:

$log_ab=\frac{log_cb}{log_ca} \\\\log_9(2x-5)=\frac{log_3(2x-5)}{log_39} = \frac{log_3(2x-5)}{2} =log_3(2x-5)^{\frac{1}{2} } =log_3\sqrt{2x-5}$