Question

6) Dadas as funções, f(x) = 2x +12, g(x) = -2x +5, h(x-3) = 3x + 1 e p(3x + 7) = -4x +11, calcule:

a) f(3)
b) f(-5)
c) g(10)
d) f(-1) + g(2)
e) h(8)
f) g(4) + h(-1)
g) g(3) + p(-5)
h) (2)​

Answer 1

Resposta:

a) 18

b) 2

c) -15

d) 11

e) 34

f ) 4

g) 26

h) 16

Explicação passo a passo:

6)

f(x) = 2x +12

g(x) = -2x +5

h(x-3) = 3x + 1

p(3x + 7) = -4x +11

a) f(3)

f(3) = 2 . 3 + 12

f(3) = 6 + 12

f(3) = 18

b) f(-5)

f(-5) = 2 . (-5) + 12

f(-5) = (-10) + 12

f(-5) = 2

c) g(10)

g(10) = -2 . 10 + 5

g(10) = -20 + 5

g(10) = -15

d) f(-1) + g(2)

f(-1) + g(2) = (2 . (-1) + 12) + (-2 . 2 + 5)

f(-1) + g(2) = -2 + 12 + (-4 + 5)

f(-1) + g(2) = 10 + 1

f(-1) + g(2) = 11

e) h(8)

h(11-3) = 3 . 11 + 1

h(8) = 33 + 1

h(8) = 34

f) g(4) + h(-1)

g(4) + h(2-3) = -2 . 4 + 5 + 3 . 2 + 1

g(4) + h(-1) = -8 + 5 + 6 + 1

g(4) + h(-1) = 5 + 6 + 1 - 8

g(4) + h(-1) = 12 - 8

g(4) + h(-1) = 4

g) g(3) + p(-5)

p(3x + 7) = p(-5) → 3x + 7 = -5 → x = (-5 -7) / 3 → x = -12/3 → x = -4

g(3) + p(3.-4+7) = -2 . 3 + 5 + (-4 . -4 + 11)

g(3) + p(-12+7) = -6 + 5 + (16 + 11)

g(3) + p(-5) = -1 + 27

g(3) + p(-5) = 26

h) h(2)​

h(5-3) = 3 . 5 + 1

h(2) = 15 + 1

h(2) = 16