Question

intégral de 3x³ dx= preciso do cálculo completo . ​

Answer 1

Integral de um monômio :

$\displaystyle \sf \int y^{n} dy = \frac{y^{(n+1)}}{n+1} + C$

Daí :

$\displaystyle \sf \int3x^3dx =\frac{3x^{(3+1)}}{3+1}+ C \to {\boxed{\sf \frac{3x^4}{4}+C}\checkmark$