• Matéria: Matemática
  • Autor: rayanneconta5550
  • Perguntado 3 anos atrás

f(x)=3²x-7x+2

f(x)=-x²+7x-2

f(x)=x²-4

f(x)=-3²+6

f(x)=x²=3x

f(x)=-x²+5x


rayanneconta5550: pfv me ajudemm;(

Respostas

respondido por: JohanLiebert
0

Resposta e explicação passo a passo:

a)\  3x^2-7x+2=0\\\\(x-2)(x-\frac{1}{3})=0\\\\x=2\ ou\ x=\frac{1}{3}\\\\\\b)\ -x^2+7x-2=0\\\\(x-\frac{7-\sqrt{41}}{2})(x+\frac{7+\sqrt{41}}{2})=0\\\\x=\frac{7-\sqrt{41}}{2}\ ou\ x=\frac{7+\sqrt{41}}{2}\\\\\\c)\ x^2-4=0\\\\(x-2)(x+2)=0\\\\x=2\ ou\ x=-2\\\\\\d)\ -3x^2+6=0\\\\(x+\sqrt{2})(x-\sqrt{2})=0\\\\x=\sqrt{2}\ ou\ x=-\sqrt{2}\\\\\\e)\ x^2-3x=0\\\\x(x-3)=0\\\\x=0\ ou\ x=3\\\\\\\\f)\ -x^2+5x=0\\\\-x(x-5)=0\\\\x=0\ ou\ x=5

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