• Matéria: Matemática
  • Autor: nilvalisboa2000
  • Perguntado 3 anos atrás

Como posso resolver?

Anexos:

Respostas

respondido por: JohanLiebert
1

Resposta:

3-\\\\a)\ 153\ cm^3\\\\b)\ 24\ cm^3\\\\c)\ 30\ cm^3\\\\4-\\\\1\º-100\ cm\\\\2\º-2,4\ m\\\\3\º-6\ cm

Explicação passo a passo:

3)\ V=B\bullet{h}\bullet{L}\\\\B=Base\\\\h=Altura\\\\L=Lado\\\\a)\ B=8,5\ cm,\ h=6\ cm\ e\ L=3\ cm\\\\V=8,5\bullet6\bullet3=153\ cm^3\\\\\\b)\ B=8\ cm,\ h=1,5\ cm\ e\ L=2\ cm\\\\V=8\bullet1,5\bullet2=24\ cm^3\\\\\\c)\ B=5\ cm,\ h=1,5\ cm\ e\ L=4\ cm\\\\V=5\bullet1,5\bullet4=30\ cm^3\\\\\\4)\\\\1\º-B=5\ cm,\ h=4\ cm,\ L=?\ cm\ e\ V=200\ cm^3\\\\200=5\bullet4\bullet{L}\\\\200=2L\\\\L=\frac{200}{2}=100\ cm

2\º-B=?\ m,\ h=5,4\ m,\ L=3,5\ m\ e\ V=37,8\ m^3\\\\37,8=B\bullet5,4\bullet3,5\\\\37,8=15,75B\\\\B=\frac{37,8}{15,75}=2,4\ m\\\\3\º-B=4\ cm,\ h=?\ cm,\ L=3\ cm\ e\ V=72\ cm^3\\\\72=4\bullet{h}\bullet3\\\\72=12h\\\\h=\frac{72}{12}=6\ cm

\left|\begin{array}{ccc}100\ cm\\3,5\ m\\3\ cm\end{array}\right\left|\begin{array}{ccc}5\ cm\\2,4\ m\\4\ cm\end{array}\right\left|\begin{array}{ccc}4\ cm\\5,4\ m\\6\ cm\end{array}\right\left|\begin{array}{ccc}200\ cm^3\\37,8\ m^3\\72\ cm^3\end{array}\right|

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