• Matéria: Matemática
  • Autor: mariajudinete
  • Perguntado 3 anos atrás

SERA Q VCS PODEM MIM AJUDAR ​

Anexos:

Respostas

respondido por: JohanLiebert
1

Resposta:

a:\ 12\\\\b:\ 60\\\\c:\ 77

Explicação passo a passo:

Voce\ tera\ que\ fazer\ o\ MMC\ em cada\ questao:\\\\a)\ \frac{1}{2},\frac{1}{3},\frac{1}{4}\\\\2,3,4\ /2\\1,3,2\ /2\\1,3,1\ /3\\ 1,1,1\\\\2\bullet2\bullet3=12\\\\b)\ \frac{3}{5},\frac{2}{6},\frac{1}{12}\\\\5,6,12\ /2\\5,3,6\ /2\\5,3,3\ /3\\5,1,1\ /5\\1,1,1\\\\2\bullet2\bullet3\bullet5=60\\\\c)\ \frac{4}{7},\frac{5}{11}\\\\7,11\ /7\\1,11\ /11\\11\\\\7\bullet11=77


mariajudinete: muito obrigado
respondido por: franciscosuassuna12
0

Explicação passo-a-passo:

a)   \frac{1}{2}  \:  \:  \:  \frac{1}{3}  \:  \:  \:   \:  \:  \:  \frac{1}{4}

m.m.c=

2, 3, 4 : 2

1, 3, 2 : 2

1, 3, 1 : 3

1, 1, 1 m.m.c =2²x3=4x3=12

  \frac{6}{12}  \:  \:  \:  \frac{4}{12}  \:  \:  \:  \frac{3}{12}

b) \frac{2}{5}  \:  \:  \:  \frac{2}{6}  \:  \:  \:  \frac{1}{12}

m.m.c=

5, 6, 12 : 2

5, 3, 6 : 2

5, 3, 3 : 3

5, 1, 1 m.m.c=2²x3x5=4x3x5=60

 \frac{24 }{60}  \:  \:  \:  \frac{20}{60}  \:  \:  \:  \frac{15}{60}

c) \frac{4}{7}  \:  \:  \:  \frac{5}{11}

.m.c=7x11=77

 \frac{44}{77}  \:  \:  \:  \frac{35}{77}

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