Question

Exercícios
1) Calcule:

Answer 1

Os resultados estão abaixo.

→ Para somar ou subtrair matrizes precisamos, antes de mais nada, que elas sejam de ordem iguais, caso contrário não é possivel tais operações.

→ Para esse cálculo basta somar (ou subtrair) os elementos que ocupam a mesma posição.

Então vamos aos cálculos:

a)

$\large \text { A= \left[\begin{array}{cc}5&1\\3&0 \end{array}\right] + \left[\begin{array}{cc}-2&6\\1&-8 \end{array}\right] = \boldsymbol{ \left[\begin{array}{cc}3&7\\4&-8 \end{array}\right]} }$

b)

$\large \text { B= \left[\begin{array}{cc}10&18\\-9&15 \end{array}\right] - \left[\begin{array}{cc}-7&0\\12&-4 \end{array}\right] = \boldsymbol{ \left[\begin{array}{cc}17&11\\-21&19 \end{array}\right]} }$

c)

$\large C= \left[\begin{array}{ccc}3&5&-8\\0&-6&1\\1&0&-2 \end{array}\right] + \left[\begin{array}{ccc}1&-5&-1\\-6&0&10\\3&2&1 \end{array}\right]$  $\large \text { = \boldsymbol{ \left[\begin{array}{ccc}4&0&-9\\-6&-6&11\\4&2&-1 \end{array}\right] } }$

d)

$\large D= \left[\begin{array}{cc}5&-2\\-3&1 \end{array}\right] + \left[\begin{array}{cc}0&-2\\9&3 \end{array}\right] - \left[\begin{array}{cc}-4&10\\-1&7 \end{array}\right]$ $\large \text { = \boldsymbol{ \left[\begin{array}{cc}9&-14\\7&-3 \end{array}\right]} }$

e)

$\large E= \left[\begin{array}{ccc}2&3&7\\1&4&2\\3&1&7 \end{array}\right] - \left[\begin{array}{ccc}0&1&01\\4&4&-2\\5&-9&8 \end{array}\right] ~$  $\large \text { ~= \boldsymbol{ \left[\begin{array}{ccc}2&2&7\\-3&0&4\\-2&10&-1 \end{array}\right] } }$

f)

$\large \text { F= \left[\begin{array}{cc}2&3\\7&5 \end{array}\right] + \left[\begin{array}{cc}1&3\\0&4 \end{array}\right] = \boldsymbol{ \left[\begin{array}{cc}3&6\\7&9 \end{array}\right]} }$

g)

$\large \text { G= \left[\begin{array}{cc}10&9\\1&4\\2&9\\5&2 \end{array}\right] - \left[\begin{array}{cc}5&8\\5^2&2\\\sqrt{4} &5\\9&1 \end{array}\right] = \boldsymbol{ \left[\begin{array}{cc}5&1\\-24&2\\ 0&4\\-4&1 \end{array}\right]} }$

h)

$\large \text { H= \left[\begin{array}{cc}23&4^3\\9&2 \end{array}\right] + \left[\begin{array}{cc}12&9\\4&1 \end{array}\right] = \boldsymbol{ \left[\begin{array}{cc}35&73\\13&3 \end{array}\right]} }$

i)

$\large \text { I= \left[\begin{array}{cc}2&9\\4&1\\6^0&0 \end{array}\right] - \left[\begin{array}{cc}-5&4\\10&15\\ 0&2 \end{array}\right] = \boldsymbol{ \left[\begin{array}{cc}7&5\\-6&-14\\ 1&-2 \end{array}\right]} }$

j)

$\large \text { J= \left[\begin{array}{c}1\\3\\2\\4 \end{array}\right] - \left[\begin{array}{c}9\\8\\5\\7 \end{array}\right] = \boldsymbol{ \left[\begin{array}{c}-8\\-5\\ -3\\-3 \end{array}\right]} }$

k)

$\large \text { K= \left[\begin{array}{cc}22&20\\6&12 \end{array}\right] - \left[\begin{array}{cc}6&20\\10&21 \end{array}\right] = \boldsymbol{ \left[\begin{array}{cc}16&0\\-4&-9 \end{array}\right]} }$

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