Question

Sendo P(x) = – 3x 4 + 3x 3 + 5x 2 – 4x +6 e R(x) = x 4 – 2x 3 – 6x 2 –3x–10 Determine: 2R( x ) – P ( x )​

Answer 1

Resposta:

$\textsf{Leia abaixo}$

Explicação passo a passo:

$\mathsf{P(x) = -3x^4 + 3x^3 + 5x^2 - 4x + 6}$

$\mathsf{R(x) = x^4 - 2x^3 - 6x^2 - 3x - 10}$

$\mathsf{2R(x) = 2(-3x^4 + 3x^3 + 5x^2 - 4x + 6)}$

$\mathsf{2R(x) = -6x^4 + 6x^3 + 10x^2 - 8x + 12}$

$\mathsf{2R(x) - P(x) = -6x^4 + 6x^3 + 10x^2 - 8x + 12 - (-3x^4 + 3x^3 + 5x^2 - 4x + 6)}$

$\mathsf{2R(x) - P(x) = -6x^4 + 6x^3 + 10x^2 - 8x + 12 +3x^4 - 3x^3 - 5x^2 + 4x - 6}$

$\boxed{\boxed{\mathsf{2R(x) - P(x) = -3x^4 + 3x^3 + 5x^2 - 4x + 6}}}$