Respostas
respondido por:
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As retas serão paralelas se seus coeficientes angulares forem iguais.
Devemos ter as equações na forma reduzida:
![4x+10y+13=0\\10y=-4x-13\\y=(-4x-13)/10\\y=(-4x/10)-(13/10)\\y=(-2/5)x - (13/10) 4x+10y+13=0\\10y=-4x-13\\y=(-4x-13)/10\\y=(-4x/10)-(13/10)\\y=(-2/5)x - (13/10)](https://tex.z-dn.net/?f=4x%2B10y%2B13%3D0%5C%5C10y%3D-4x-13%5C%5Cy%3D%28-4x-13%29%2F10%5C%5Cy%3D%28-4x%2F10%29-%2813%2F10%29%5C%5Cy%3D%28-2%2F5%29x+-+%2813%2F10%29)
![m_{1}=-2/5 m_{1}=-2/5](https://tex.z-dn.net/?f=m_%7B1%7D%3D-2%2F5)
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![6x+ky+11=0\\ky=-6x-11\\y=(-6x-11)/k\\y=(-6x/k)-(11/k)\\y=(-6/k)x - (11/k) 6x+ky+11=0\\ky=-6x-11\\y=(-6x-11)/k\\y=(-6x/k)-(11/k)\\y=(-6/k)x - (11/k)](https://tex.z-dn.net/?f=6x%2Bky%2B11%3D0%5C%5Cky%3D-6x-11%5C%5Cy%3D%28-6x-11%29%2Fk%5C%5Cy%3D%28-6x%2Fk%29-%2811%2Fk%29%5C%5Cy%3D%28-6%2Fk%29x+-+%2811%2Fk%29)
![m_{2}=-6/k m_{2}=-6/k](https://tex.z-dn.net/?f=m_%7B2%7D%3D-6%2Fk)
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![m_{1}=m_{2}\\-2/5=-6/k\\2/5=6/k\\1/5=3/k\\k*1=3*5\\\\\boxed{\boxed{k=15}} m_{1}=m_{2}\\-2/5=-6/k\\2/5=6/k\\1/5=3/k\\k*1=3*5\\\\\boxed{\boxed{k=15}}](https://tex.z-dn.net/?f=m_%7B1%7D%3Dm_%7B2%7D%5C%5C-2%2F5%3D-6%2Fk%5C%5C2%2F5%3D6%2Fk%5C%5C1%2F5%3D3%2Fk%5C%5Ck%2A1%3D3%2A5%5C%5C%5C%5C%5Cboxed%7B%5Cboxed%7Bk%3D15%7D%7D)
Devemos ter as equações na forma reduzida:
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emicosonia:
Puxa vida!!!! gostei da resolução!!! bem didatica
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