Question

2) Calcule X, aplicando o conceito de trigonometria:

alguém me ajuda prfvr

Answer 1

$a) x = 5\sqrt[2]{3}\\ b) x = 15$

$a) sen60^0 = cateto\ oposto / hipotenusa\\\sqrt[2]{3} / 2 = x / 12 \\\\2x = 12.\sqrt[2]{3}\\\\x = 12\sqrt[2]{3}/2\\\\\\x = 6.\sqrt[2]{3}$

$b) tg45^0 = cateto\ oposto / cateto\ adjacente\\\\1 = 15 / x\\\\x = 15$

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