Question

1) CALCULE:

A) 3^2+3^-2=
B) 2^0+2^1+2^-1=
C) (1/2)^-1+(1/2)^-2=
D) 2/3+(-1/3)^2=
E) (-1/2)^2-3^2=

Answer 1

Resposta:

Explicação passo a passo:

$A) 3^2+3^{-2}= 9 + \frac{1}{3^2}=9 + \frac{1}{9}=\frac{81+1}{9} = \frac{82}{9}\\B) 2^0+2^1+2^{-1}= 1 + 2 + \frac{1}{2} = 3 + \frac{1}{2}=\frac{6+1}{2}=\frac{7}{2}\\C) \frac{1}{2}^{-1}+\frac{1}{2}^{-2}= 2 + 2^2=2+4=6\\D) \frac{2}{3}+\frac{-1}{3}^2= \frac{2}{3}+\frac{1}{9}=\frac{6+1}{9}=\frac{7}{9}\\E) \frac{-1}{2}^2-3^2= \frac{1}{4}-9=\frac{1-36}{4}=\frac{-35}{4}$