Question

Calcule a, b e c, onde a/2=b/3=c/5 e 2a + 3b – c =150

Answer 1

$a/2=b/3=c/5\\\\a/2=b/3\\b=3a/2\\\\a/2=c/5\\c=5a/2$

$2a+3b-c=150\\2a+3(3a/2)-(5a/2)=150$

Multiplicando todos os membros da equação por 2:

$2.2a+2.3(3a/2)-2(5a/2)=2.150\\4a+3(3a)-5a=300\\4a+9a-5a=300\\8a=300\\a=300/8\\a=75/2$

$b=3a/2\\b=3(75/2)/2\\b=3(75/4)\\b=225/4$

$c=5a/2\\c=5(75/2)/2\\c=5(75/4)\\c=375/4$