Question

determine o vertice das seguintes funções :​

Answer 1

Explicação passo-a-passo:

x²+x+1=0

a=1

b=1

c=1

∆=b²-4ac

∆=1²-4*1*1

∆=1-4

∆=-3

Xv=-b/2a

Xv=-1/2*1

Xv=-1/2

Yv=-∆/4a

Yv=3/4*1

Yv=3/4

Vértice =>{ -1/2 e 3/4}

x²-9=0

a=1

b=0

c=-9

∆=b²-4ac

∆=0²-4*1*-9

∆=0+36

∆=36

Xv=-b/2a

Xv=-0/2*-9

Xv=-0/-18

Xv=0

Yv=-∆/4a

Yv=-36/4*1

Yv=-36/4

Yv=-9

Vértice =>{ 0 e -9}

-x²+4x-4=0

a=-1

b=4

c=-4

∆=b²-4ac

∆=4²-4*-1*-4

∆=16-16

∆=0

Xv=-b/2a

Xv=-4/2*-1

Xv=-4/-2

Xv=2

Yv=-∆/4a

Yv=-0/4*-1

Yv=-0/-4

Yv=0

Vértice =>{ 2 e 0}

-x²-8x=0

a=-1

b=-8

c=0

∆=b²-4ac

∆=(-8)²-4*-1*0

∆=64-0

∆=64

Xv=-b/2a

Xv=8/2*-1

Xv=-8/2

Xv=-4

Yv=-∆/4a

Yv=-64/4*-1

Yv=-64/-4

Yv=16

Vértice =>{ -4 e 16}