Question

3. No triângulo retângulo da figura, calcule: a) sen a b) cos a c) tg a d) sen b e) cos b f) tg b​

Answer 1

Explicação passo-a-passo:

$\sin( \alpha ) = \frac{12}{13} \\ \cos( \alpha ) \frac{5}{13} \\ \tan( \alpha ) = \frac{ \sin( \alpha ) }{ \cos( \alpha ) } = \frac{ \frac{12}{13} }{ \frac{5}{13} } = \frac{12}{13} \times \frac{13}{5} = \frac{12}{5} \\ \sin( \beta ) = \frac{5}{13} \\ \cos( \beta ) = \frac{12}{13} \\ \tan( \beta ) = \frac{ \sin( \beta ) }{ \cos( \beta ) } = \frac{ \frac{5}{13} }{ \frac{12}{13} } = \frac{5}{13} \times \frac{13}{12} = \frac{5}{12}$