Question

:4) Calcule 2 p(1)-p(-1)-3p(0) em: p(x)=3x³+2x²+1​

Answer 1

Resposta:

Explicação passo a passo:

p(1)=

3.1³+2.1²+1=

3+2+1=

6

p(-1)=

3(-1)³+2.(-1)²+1=

3.-1+2.1+1=

-3+2+1=

-1+1=

0

p(0)=

3.0³+2.0²+1=

0+0+1=

1

2p(1)-p(-1)-3p(0)=

2.6-0-3.1=

12-0-3=

12-3=

9