Question

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Answer 1

Resposta:

a) 6+3×[(5×3-16÷2)+(4÷1+4×5)] =

6+3×[(15-8)+(4+20)] =

6+3×[7+24] =

6+3×31 =

6+93 = 99

b) [9×(3+1)-21÷(1+6)]-[2×(2+7)-15÷(6+9)] =

[9×4-21÷7]-[2×9-15÷15] =

[36-3]-[18-1] =

12-17 = -5

c) 10+[2×(5+8)-20÷(1+4)]÷[(4×3-12÷3)÷4] =

10+[2×13-20÷5]÷[(12-4)÷4] =

10+[26-4]÷[8÷4] =

10+22÷2 =

10+11 = 21