• Matéria: Matemática
  • Autor: juliacastroh
  • Perguntado 3 anos atrás

A) (x+5).(x+3) = B) (x+2) (x+6) C) (x-7) (x+3) D) (x-1) (x-6) E) (x+10) (x-9) F) (3x+2) (2x+6)

Respostas

respondido por: albertrieben
0

Vamos là.

A) (x + 5) (x + 3) = x² + 8x + 15

B) (x + 2) (x + 6) = x² + 8x + 12

C) (x-7) (x+3) = x²- 4x - 21

D) (x-1) (x-6) = x² - 7x + 6

E) (x+10) (x-9) = x² + x - 90

F) (3x+2) (2x+6) = 6x²+ 22x + 12

respondido por: Anônimo
1

a) \\ (x + 5) x (x+3) \\ X \times X + 3x + 5x + 5x3 \\ x {}^{2} + 3x + 5x + 15 \\  {\red{x {}^{2}+ 8x + 15 }} \\  \\ b) \\ (x + 2)x(x+6) \\X \times X + 6x + 2x + 2×6 \\ x {}^{2} + 6x + 2x + 12 \\  {\red{x {}^{2} + 8x + 12}}  \\  \\ c) \\ (x-7) x (x+3) \\ x \times x+3x - 7x-7x3 \\ x {}^{2}+3x-7x - 21 \\  {\red{x {}^{2}- 4x -  21 }} \\  \\ d) \\(x-1)×(x-6) \\  x \times x-6x-x-1 \times ( - 6) \\ x {}^{2}  - 6x - x + 6 \\  {\red{x {}^{2}-7x+6 }} \\ \\  e) \\ (x + 10) \times (x - 9) \\ x \times x - 9x + 10x - 10 \times 9 \\ x {}^{2}  - 9x + 10x - 90 \\  {\red{x {}^{2} + x - 90 }} \\ \\  f) \\ (3x + 2) \times (2x + 16) \\ 3x \times 2x + 3x \times 6 + 2 \times 2x + 2 \times 6 \\ 6x {}^{2} + 18x + 4x + 12 \\  {\red{6x {}^{2} + 22x + 12 }} \\  \\ \sf \colorbox{blue}{espero \: ter \: ajudado}

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