Question

Calcule o limite da função (x^3-8)/(x-2), com x tendendo a 2.

Answer 1

$\lim_{x \to 2} \frac{x ^{3} -8}{x-2} = \frac{2 ^{3} -8}{2-2} = \frac{0}{0} = indeterminacao$

Resolvendo o limite temos :
$\lim_{x\to2} \frac{(x-2)(x^{2}+2x+4) }{x-2} = x^{2} +2x+4= 2 ^{2} +2.2+4=12.$