Question

5x2+2x-3=0,Formula de baskara e delta

Answer 1

Resposta:

Explicação passo a passo:

$5x^2+2x-3=0\\a=5, b=2, c=-3$

Δ$=b^2-4.a.c$

$2^2-4.5.(-3)\\4+60\\64$

$\frac{-5+_-\sqrt{64}} {2.5}\\\\\frac{-5+_-8}{10}\\\\x'=\frac{-5+8}{10}==>\frac{3}{10}\\\\x''=\frac{-5-8}{10}==>\frac{-13}{10}$