Question

Resolva as equações abaixo​

Answer 1

Resposta:

a) x² + 5x + 6 = 0

Δ = b² - 4ac

Δ = 5² - 4 · 1 · 6

Δ = 25 - 24

Δ = 1

x = (-b ±√Δ) / 2a

x = (-5 ±√1) / 2

x' = - 5 + 1 / 2

x' = -2

x'' = -5 -1 / 2

x'' = -3

S = {-2, -3}

b) x² - 14x + 49 = 0

Δ = (-14)² - 4 · 1 · 49

Δ = 196 - 196 = 0

x = (-(-14) ±√0) / 2

x = 14 ± 0 / 2

x = 7

S = {7}