Question

Calcule o raio da circunferência ao triângulo nos casos :​

Answer 1

Resposta:

$\textsf{Leia abaixo}$

Explicação passo a passo:

$\mathsf{sen\:{\^A} = \dfrac{a}{2R}}$

$\mathsf{sen\:30\textdegree = \dfrac{4}{2R}}$

$\mathsf{\dfrac{1}{2} = \dfrac{4}{2R}}$

$\boxed{\boxed{\mathsf{R = 4}}}$

$\mathsf{sen\:{\^A} = \dfrac{a}{2R}}$

$\mathsf{sen\:60\textdegree = \dfrac{14}{2R}}$

$\mathsf{\dfrac{\sqrt{3}}{2} = \dfrac{14}{2R}}$

$\mathsf{R = \dfrac{14}{\sqrt{3}}}$

$\boxed{\boxed{\mathsf{R = \dfrac{14\sqrt{3}}{3}}}}$

$\mathsf{sen\:{\^A} = \dfrac{a}{2R}}$

$\mathsf{sen\:135\textdegree = \dfrac{10}{2R}}$

$\mathsf{\dfrac{\sqrt{2}}{2} = \dfrac{10}{2R}}$

$\mathsf{R = \dfrac{10}{\sqrt{2}}}$

$\boxed{\boxed{\mathsf{R = 5\sqrt{2}}}}$