Question

Me ajudem a responder a 2° questão urgente ​

Answer 1

Resposta:

x = 4 ou x = 2

Explicação passo a passo:

$\sqrt{x^{2} - 6x + 16} = 2\sqrt{2\\ } \\\\ (\sqrt{x^{2} - 6x + 16})^{2} = (2\sqrt{2\\ })^{2}\\\\x^{2} - 6x + 16 = 8\\\\x^{2} - 6x + 8 = 0\\\\\alpha = b^{2} - 4.a.c\\\\\alpha = (-6)^{2} - 4.8\\\\\alpha = 36 - 32 = 4\\\\x_1 =\frac{-b + \sqrt{\alpha}}{2.a} } =\frac{6 + \sqrt{4}}{2} } = 4\\\\x_2=\frac{-b - \sqrt{\alpha}}{2.a} } = \frac{6 - \sqrt{4}}{2} } = 2$