Question

Calcule 7²+2.[(3+1)²-4x1³]

Answer 1

$<var>7^2+2[(3+1)^2-4 \cdot 1^3]=</var>$

$<var>49+2[4^2-4 \cdot 1]=</var>$]

49+2[16-4]=

49+2.12=

49+24= 73