Question

1-determine

a)
$- \sqrt[3]{729}$


b)
$\sqrt{0.01}$


c)
$\sqrt[5]{ - 243}$


d)
$\sqrt[3]{ \frac{1}{8} }$


e)
$\sqrt[3]{ \frac{1}{32} }$


preciso pra hoje pôr favor

quem responde primeiro sou a melhor resposta ✌​

Answer 1

Resposta:

$a) \: - \sqrt[3]{729} = \blue{- 9}$

$b) \: \sqrt{0.01} = \sqrt{ \frac{1}{100} } = \blue{\frac{1}{10}}$

$c) \: \sqrt[5]{ - 243} = \blue{ - 3}$

$d) \: \sqrt[3]{ \frac{1}{8} } = \blue{ \frac{1}{2} }$

$e) \: \sqrt[3]{ \frac{1}{32} } = \frac{1}{ \sqrt[3]{2 {}^{5} } } = \frac{1}{ \sqrt[3]{ {2}^{3} \times {2}^{2} } } = \frac{1}{2 \sqrt[3]{ {2}^{2} } } = \frac{1}{ 2\sqrt[3]{2 {}^{2} } } \times \frac{ \sqrt[3]{2 {}^{} } }{ \sqrt[3]{2 {}^{} } } = \frac{ \sqrt[3]{2 {}^{} } }{2 \sqrt[3]{2 {}^{2} \times 2 } } = \frac{ \sqrt[3]{2} }{2 \sqrt[3]{2 {}^{3} } } = \frac{ \sqrt[3]{2} }{2 \times 2} = \blue{\frac{ \sqrt[3]{2} }{4} }$