Question

calcule o valor dos logaritmos log27 ⁵√3​

Answer 1

Resposta:

$\textsf{Leia abaixo}$

Explicação passo a passo:

$\mathsf{log_{27}\:\sqrt[5]{3} = x}$

$\mathsf{27^x = \sqrt[5]{3}}$

$\mathsf{(3^3)^x = 3^{\frac{1}{5}}}$

$\mathsf{3^{3x} = 3^{\frac{1}{5}}}$

$\mathsf{3x = \dfrac{1}{5}}$

$\boxed{\boxed{\mathsf{log_{27}\:\sqrt[5]{3} = \dfrac{1}{15}}}}$