• Matéria: Matemática
  • Autor: leocc29
  • Perguntado 3 anos atrás

dy/dx para y= 4/cos(x)+1/tag (x)

Respostas

respondido por: ReijiAkaba
0

\dfrac{dy}{dx} =4\dfrac{d}{dx}\bigg(\dfrac{1}{\cos(x)}\bigg)+\dfrac{d}{dx}\bigg(\dfrac{1}{\tan(x)}\bigg)=4\dfrac{d}{dx}(\sec(x))+\dfrac{d}{dx}(\cot(x))=\\\\=4\sec(x)\tan(x)-\csc^2(x)

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