Question

Ao lançarmos dois dados de seis faces, qual a probabilidade de a soma entre as duas que saírem ser igual a 6?​

Answer 1

$p(e) = \frac{n(e)}{n(6)} = \frac{f}{t} \\ \\ (t) \: d1 > > (1,2,3,4,5,6) \\ d2 > > (1,2,3,4,5,6) \\ \\ s = (1,1),(1,2),(1,3),(1,4),(1,5),(1,6), \\ (2,1),(2,2),(2,3),(2,4),(2,5),(2,6), \\ (3,1),(3,2),(3,3),(3,4),(3,5),(3,6), \\ (4,1),(4,2),(4,3),(4,4),(4,5),(4,6), \\ (5,1),(5,2),(5,3),(5,4),(5,5),(5,6), \\ (6,1),(6,2),(6,3),(6,4),(6,5),(6,6) \\ \\ n(s) = 6 \times 6 = 36 \\ \\( f) = (1,5),(2,4),(3,3),(4,2),(5,1) \\ \\n(e) = 5 \\ \\ \boxed{ \frac{5}{36} }$

resposta >>> 5/36