Question

1) Realizar as operações abaixo usando potência de base 10.

$a) \: \frac{9,6}{3,2} \frac{ \times }{ \times } \frac{ {10}^{13} }{ {10}^{10} }$

$b) \: 7,36 \times {10}^{16} \times 3 \times {10}^{4}$

$c) \: 0,5 \times {10}^{11} + 22,4 \times {10}^{8}$

$d) \: 802 \times {10}^{12} - 52 \times {10}^{13}$

$e) \: \frac{3,2}{4} \frac{ \times }{ \times } \frac{ {10}^{ - 3} }{ {10}^{ - 16} }$

$f) \: \frac{0,009 } {3000} =$

$g) \: \frac{5000 \: \times \: 0,04 }{0,0008}$

$h) \: \frac{2200000 \: \times 0,04}{0.005 \: \times \: 0.2}$

$i) \frac{0.0004 \: \times \: 700 \times 0,0032}{800000 \times 0,001}$

$j) \: \frac{ \sqrt{10000 \: \times 4 \: \times \sqrt{0,0001} } }{0,0004}$

$k) \: \frac{ \sqrt{ {10}^{20 \: \times \:2,5 \: \sqrt{10 { - 8}^{} } } } }{0,00025}$

​

Answer 1

Resposta:

:

a) 3 . 10^{3}3.103

b) 2,208. 10^{21}2,208.1021

c) 5,0224 . 10^{11}5,0224.1011

d)2,87 . 10^{14}2,87.1014

e) 8 . 10^{12}8.1012

f)3 . 10^{-6}3.10−6

g)2,5 . 10^{10}2,5.1010

Explicação:

a) \frac{9,6}{3,2} . 10^{13-10}3,29,6.1013−10 = 3 . 10^{3}3.103

b)  7,36 . 3 . 10^{16+4}7,36.3.1016+4 = 22,08 . 10^{20}22,08.1020 = 2,208. 10^{21}2,208.1021

c) 500 . 10^{9} + 2,24 . 10^{9} = 502,24 . 10^{9} = 5,0224 . 10^{11}500.109+2,24.109=502,24.109=5,0224.1011

d)80,2 . 10^{13} - 52. 10^{13} = 28,7 .10^{13} = 2,87 . 10^{14}80,2.1013−52.1013=28,7.1013=2,87.1014

e) \frac{3,2}{4} . 10^{-3-(-16)}43,2.10−3−(−16) =  0,8 . 10^{13} = 8 . 10^{12}0,8.1013=8.1012

f)  \frac{9 . 10^{-3} }{3 . 10^{3} } = \frac{9}{3} . 10^{-3-3} = 3 . 10^{-6}3.1039.10−3=39.10−3−3=3.10−6

g)  \frac{2000}{0,0008} =\frac{2 . 10^{3} }{8 . 10^{-8} } =\frac{2}{8} . 10^{3-(-8)}= 0,25 . 10^{11} = 2,5 . 10^{10}0,00082000=8.10−82.103=82.103−(−8)=0,25.1011=2,5.1010