Question

5) Encontre x' e x'' 2X²-12x+18 ​

Answer 1

$∆ = {b}^{2} - 4.a.c \\ ∆ = ( - 12) - 4.2.18 \\ ∆ = 144 - 144 \\ ∆ = 0 \\ \\ x = \frac{ - b \pm \sqrt{∆} }{2.a} \\ \\ x' = x" = \frac{ - 12}{4} \\ \\ x' = x" = - 3$