Question

Derivada de
$y=cos e^4^x$

Answer 1

$\\ y = Cos(e^4^x) \\ \\ y' = [Cos(e^4^x)]'*(e^4^x)*(4x)' \\ \\ y' = -Sen(e^4^x)*e^4^x*4 \\ \\ y' = -4e^4^xSen(e^4^x)$

Answer 2

$\sf \displaystyle y=cose^{4x}\\\\\\\frac{d}{dx}\left(\cos \left(e^{4x}\right)\right)\\\\\\=-\sin \left(e^{4x}\right)\frac{d}{dx}\left(e^{4x}\right)\\\\\\\to \boxed{\sf =-\sin \left(e^{4x}\right)e^{4x}\cdot \:4}$