• Matéria: Matemática
  • Autor: godoyleticia027
  • Perguntado 3 anos atrás

A)5(2X+7)-1=4(X-5)
B)2(X-1)+3(X-1)=4(X+2)
C)2(B+1)+5(B+1)=4
D)2(2W+3)+5(W+1)=8-3(W-1)
ELIMINANDO PARENTESES
PRECISO PRA AMANHA

Respostas

respondido por: vitoria4872
0

A) 5(2X + 7) - 1 = 4(X - 5)

10X + 35 - 1 = 4(X - 5)

10X + 34 = 4(X - 5)

10X + 34 = 4X - 20

10X + 34 - 4X = 4X - 20 - 4X

6X + 34 = - 20

6X + 34 - 34 = - 20 - 34

6X = - 54

(6x)/6 = - 54/6

X= -9

B) 2(X - 1) + 3(X - 1) = 4(X + 2)

(2 + 3)(X - 1) = 4(X + 2)

5(X - 1) = 4(X + 2)

5X - 5 = 4(X + 2)

5X - 5 = 4X + 8

5X - 5 - 4X = 4X + 8 - 4X

X - 5 = 8

X - 5 + 5 = 8 + 5

X= 13

C) 2(B + 1) + 5(B + 1) = 4

(2 + 5)(B + 1) = 4

7(B + 1) = 4

7B + 7 = 4

7B + 7 - 7 = 4 - 7

7B = - 3

(7B)/7 = - 3/7

B = - 0.42857i

B = - 3/7

D) 2*(2W+3)+5*(W+1)=8-3*(W*

4W + 6 + 5(W + 1) = 8 - 3(W - 1)

4W + 6 + 5W + 5 = 8 - 3(W - 1)

4W + 6 + 5W + 5 = 8 - (3W - 3)

4W + 6 + 5W + 5 = - 3W + 11

9W + 11 = - 3W + 11

9W + 11 + 3W = - 3W + 11 + 3W

12W + 11 = 11

12W + 11 - 11 = 11 - 11

12W = 0

(12W)/12 = 0/12

W = 0

Perguntas similares