Question

Derivar:

f(x)=sen x .cos x

Answer 1

$f'(x) = cos^2x - sen^2x$

Derivada do produto

$f(x) = u.v\\\\f'(x) = u'.v + uv'\\\\u = senx\\\\u' = cosx\\\\v = cosx\\\\v' = -senx$

$f'(x) = cosx.cosx + senx.(-senx)\\\\f'(x) = cox^2x - sen^2x$

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