Question

Determine os valores de X que resolvem a equação 2X2 - 12X + 16 = 0

Answer 1

x=2 ou x=4

Explicação passo-a-passo:

$\boxed{\sf{2x^{2}-12x+16=0}}$

• $\sf{a=2}$

• $\sf{b=-12}$

• $\sf{c=16}$

• $\sf{\Delta=b^{2}-4.a.c}$

• $\sf{\Delta=(-12)^{2}-4.(2).(16)}$

• $\sf{\Delta=144-128}$

• $\sf{\Delta=16}$

• $\sf{x'=(12+√16)/2.(2)}$

• $\sf{=(12+4)/4}$

• $\sf{=16/4}$

• $\sf{ 4}$

• $\sf{x"=(12-√16)/2.(2)}$

• $\sf{=(12-4)/4}$

• $\sf{x"=8/4}$

• $\sf{x"= 2}$

As raízes serao : 2 e 4

Answer 2

Explicação passo-a-passo:

2x²-12x+16=0

Reduzindo

2x²-12x+16=0(÷2)

x²-6x+8=0

a=1

b=-6

c=8

∆=b²-4ac

∆=(-6)²-4*1*8

∆=36-32

∆=4

-b±√∆/2a

6±√4/2*1

6±2/2

x¹=6+2/2=8/2=>4

x²=6-2/2=4/2=>2