Question

resolva as equações do 2° grau

1) x²-5x+ 6 = 0 (R: 2, 3)​

Answer 1

Resposta:

$x_{1}$ = 3   $x_{2}$ = 2

Explicação passo a passo:

$x^{2}$ - 5$x$ + 6 =

a = 1   b = -5   c = 6

$x$ = -b ± √$b^{2}$ - 4ac / 2a

$x_{1}$ = 5 + √25 - 24 / 2

$x_{1}$ = 5 + 1 / 2

$x_{1}$ = 6 / 2

$x_{1}$ = 3

$x_{2}$ = 5 - √25 - 24 / 2

$x_{2}$ = 5 - 1 / 2

$x_{2}$ = 4 / 2

$x_{2}$ = 2

espero te ajudo:)

Answer 2

Resposta:

$\textsf{Leia abaixo}$

Explicação passo a passo:

$\mathsf{x^2 - 5x + 6 = 0}$

$\mathsf{\Delta = b^2 - 4.a.c}$

$\mathsf{\Delta = (-5)^2 - 4.1.6}$

$\mathsf{\Delta = 25 - 24}$

$\mathsf{\Delta = 1}$

$\mathsf{x = \dfrac{-b \pm \sqrt{\Delta}}{2a} = \dfrac{5 \pm \sqrt{1}}{2} \rightarrow \begin{cases}\mathsf{x' = \dfrac{5 + 1}{2} = \dfrac{6}{2} = 3}\\\\\mathsf{x'' = \dfrac{5 - 1}{2} = \dfrac{4}{2} = 2}\end{cases}}$

$\boxed{\boxed{\mathsf{S = \{3;2\}}}}$