Question

5. Se x = 105°, então sen xé 672-2 a) 8 63-7 b) 4 c) 7V3-5 8 (3+2)3 8 d) e) (1+13)V2 4​

Answer 1

sen 105 = sen(45 + 60) = sen45.cos60+ sen 60.cos45
sen(105)= \/2/2.1/2+\/3/2.\/2/2
Sen (105)=\/2/4+\/6/4

Sen(105) = \/2(1+\/3)/4

RESPOSTA: E