Question

Log na base 8 logaritmando 2✓2indice 3

Answer 1

Vamos là.

log8( (2√2)^3 ) =

log((2√2)^3)/(3log(2)) =

log(16√2)/log(8) =  

log(16)/log(8) + log(√2)/log(8)

= 4/3 + log(√2)/log(√2^6)

= 4/3 + 1/6 = 9/6 = 3/2