Question

calcule as potências :

a)4-²
b)4-³
c)5-¹
d)3-³
e)10-²
f)10-³
g)2-⁵
h)7-¹
i)1-¹⁸​

Answer 1

Resposta:

Explicação passo a passo:

A) 4-²= 1/4² = 1/4.4 = 1/16

B) 4-³= 1/4³ = 1/64

C) 5-¹= 1/5

D) 3-³= 1/3³ = 1/27

E) 10-²= 1/10² = 1/100

F) 10-³= 1/10³ = 1/1000

G) 2-⁵= 1/2⁵ = 1/32

H) 7-¹= 1/7

I) 1-¹⁸= 1

Answer 2

Explicação passo-a-passo:

$a)4 {}^{ - 2} = ( \frac{1}{4} ) = \frac{1}{4} \times \frac{1}{4} = \frac{1}{16}$

$b) 4 {}^{ - 3} = ( \frac{1}{4} ) {}^{3} = \frac{1}{4} \times \frac{1}{4} \times \frac{1}{4} = \frac{1}{64}$

$c)5 {}^{ - 1} = \frac{1}{5}$

$d)3 {}^{ - 3} = ( \frac{1}{3} ) {}^{3} = \frac{1}{3} \times \frac{1}{3} \times \frac{1}{3} = \frac{1}{27}$

$e)10 {}^{ - 2} = ( \frac{1}{10} ) {}^{2} = \frac{1}{10} \times \frac{1}{10} = \frac{1}{100}$

$e)10 {}^{ - 3} = ( \frac{1}{10} ) {}^{3} = \frac{1}{10} \times \frac{1}{10} \times \frac{1}{10} = \frac{1}{1000}$

$f)2 {}^{ - 5} = ( \frac{1}{2} ) {}^{5} = \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} = \frac{1}{32}$

$h)7 {}^{ - 1} = \frac{1}{7}$

$i)1 {}^{ - 18} = ( \frac{1}{1} ) {}^{18} = 1$