Question

O valor de x na equação exponencial abaixo é igual a:
9^-x=27^2x+1

Answer 1

$\large\boxed{\begin{array}{l}\rm9^{-x}=27^{2x+1}\\\rm (3^2)^{-x}=(3^3)^{2x+1}\\\rm -2x=6x+3\\\rm 6x+2x=-3\\\rm 8x=-3\\\rm x=-\dfrac{3}{8}\blue\checkmark\end{array}}$