• Matéria: Matemática
  • Autor: carmengerman9863
  • Perguntado 3 anos atrás

2x+y=5 x-3y=6 calcula sobre o método de substituição

Respostas

respondido por: CyberKirito
0

\large\boxed{\begin{array}{l}\sf Determine\,a\,soluc_{\!\!,}\tilde ao\,do\,sistema\\\sf usando\,o\,m\acute etodo\,da\,substituic_{\!\!,}\tilde ao.\\\begin{cases}\sf 2x+y=5\\\sf x-3y=6\end{cases}\end{array}}

\large\boxed{\begin{array}{l}\underline{\sf soluc_{\!\!,}\tilde ao\!:}\\\begin{cases}\rm 2x+y=5\\\rm x-3y=6\end{cases}\\\rm x-3y=6\longrightarrow x=3y+6\\\rm 2x+y=5\\\rm 2\cdot(3y+6)+y=5\\\rm 6y+12+y=5\\\rm 7y=5-12\\\rm 7y=-7\\\rm y=-\dfrac{7}{7}\\\\\rm y=-1\\\rm   x-3y=6\\\rm x-3\cdot(-1)=6\\\rm x+3=6\\\rm x=6-3\\\rm x=3\\\rm S=\{(3,-1)\}\end{array}}

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