Respostas
respondido por:
1
(x²+3x)/(x²-1) - (5x)/(x+1) = (x)/(x-1)
(x²+3x)/[(x+1)(x-1)] - (5x)/(x+1) = (x)/(x-1)
x²+3x - 5x(x-1) = x(x+1)
x²+3x-5x²+5x = x²+x
-5x²+7x = 0
5x²-7x = 0
x(5x-7) = 0
x = 0 ó 5x-7 = 0
x = 0 ó x = 7/5
(x²+3x)/[(x+1)(x-1)] - (5x)/(x+1) = (x)/(x-1)
x²+3x - 5x(x-1) = x(x+1)
x²+3x-5x²+5x = x²+x
-5x²+7x = 0
5x²-7x = 0
x(5x-7) = 0
x = 0 ó 5x-7 = 0
x = 0 ó x = 7/5
respondido por:
1
x * (x - 2) = 1 - 2x
x² - 2x = 1 - 2x
x² - 2x + 2x = 1
x² = 1
x = √1
x1 = 1 x2 = -1
x² - 2x = 1 - 2x
x² - 2x + 2x = 1
x² = 1
x = √1
x1 = 1 x2 = -1
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