Question

Me ajudem nesses cálculos de trigonometria estou precisando urgente , agradeço

Answer 1

Resposta:

Explicação passo a passo:

$1)\frac{y}{6}=sen30\°\\\\\frac{y}{6} =\frac{1}{2} \\\\2y=6\\\\y=\frac{6}{2}\\\\y=3$

$b) \frac{x}{6} =sen60\°\\\\\frac{x}{6}=\frac{\sqrt{3} }{2} \\\\2x=6\sqrt{3} \\\\x=3\sqrt{3} \\\\\\\frac{y}{6}=cos60\°\\\\\frac{y}{6} =\frac{1}{2}\\\\2y=6 \\\\y=3$