Question

Sabendo que sen 40º = 0,64; cos 40º = 0,77 e tg 40° = 0,84, determine as medidas x e y indicadas no triângulo retângulo. ​

Answer 1

$\large\displaystyle\text{ \mathsf{cos~(40^\circ)=\frac{CA}{H}} }\\\\0,77=\frac{y}{7}\\\\y=0,77\cdot7\\\\\boxed{y=5,39}\checkmark\\\\\large\displaystyle\text{ \mathsf{sen~(40^\circ)=\frac{CO}{H}} }\\\\0,64=\frac{x}{7}\\\\x=0,64\cdot7\\\\\boxed{x=4,48}\checkmark$