Question

Quanto é:

[(8^2 + 6^2) : 1^6] *2 - 1% - (log de 1024 na base 2) * (raiz de 144%) = ?

Answer 1

Resposta:

[(8² + 6²) : 1⁶] *2 - 1% - (log₂ 1024 ) * (√144%)

[(8² + 6²) : 1⁶] *2 - (1/100) - (log₂ 2¹⁰ ) * (√(144/100))

[(64 + 36) : 1] * 2 - (1/100) - (10* log₂ 2 ) * (√(12²/10²))

[100 : 1] * 2 - (1/100) - (10* 1 ) * (12/10)

100 * 2 - (1/100) - 10 * (12/10)

200 - (1/100) - 12

188-0,01

=187,99