Dada a função , calcule a primeira derivada e, em seguida assinale a alternativa CORRETA.
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Respostas
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Boa tarde!
Solução!
Vamos escrever os dados a função.
![y=sen(3 x^{2} +4)\\\\\\\\
u=3 x^{2} +4\\\\\
u'=6x\\\\\
Derivada~~de~~seno(x)=cos(x)\\\\\\
y'=cos(u).u' \\\\\
y'=cos(3 x^{2} +4).6x\\\\\
y'=6xcos(3 x^{2} +4)\\\\\\\
\boxed{ y=sen(3 x^{2} +4)=y'=6xcos(3 x^{2} +4)}\\\\
\boxed{Resposta:Alternativa~~B}](https://tex.z-dn.net/?f=y%3Dsen%283+x%5E%7B2%7D+%2B4%29%5C%5C%5C%5C%5C%5C%5C%5C%0Au%3D3+x%5E%7B2%7D+%2B4%5C%5C%5C%5C%5C%0Au%27%3D6x%5C%5C%5C%5C%5C%0A%0ADerivada%7E%7Ede%7E%7Eseno%28x%29%3Dcos%28x%29%5C%5C%5C%5C%5C%5C%0Ay%27%3Dcos%28u%29.u%27+%5C%5C%5C%5C%5C%0Ay%27%3Dcos%283+x%5E%7B2%7D+%2B4%29.6x%5C%5C%5C%5C%5C%0Ay%27%3D6xcos%283+x%5E%7B2%7D+%2B4%29%5C%5C%5C%5C%5C%5C%5C%0A%5Cboxed%7B+y%3Dsen%283+x%5E%7B2%7D+%2B4%29%3Dy%27%3D6xcos%283+x%5E%7B2%7D+%2B4%29%7D%5C%5C%5C%5C%0A%0A%5Cboxed%7BResposta%3AAlternativa%7E%7EB%7D%0A%0A "y=sen(3 x^{2} +4)\\\\\\\\
u=3 x^{2} +4\\\\\
u'=6x\\\\\
Derivada~~de~~seno(x)=cos(x)\\\\\\
y'=cos(u).u' \\\\\
y'=cos(3 x^{2} +4).6x\\\\\
y'=6xcos(3 x^{2} +4)\\\\\\\
\boxed{ y=sen(3 x^{2} +4)=y'=6xcos(3 x^{2} +4)}\\\\
\boxed{Resposta:Alternativa~~B}")
Boa tarde!
Bons estudos!
Solução!
Vamos escrever os dados a função.
Boa tarde!
Bons estudos!
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