Question

${2}^{3} + ( \sqrt{4} + 2 \times (1 + 3 - (4 \div 2))) = \:$
ajuda por favor ​

Answer 1

Resposta:

$2^3+\left(\sqrt{4}+2\left(1+3-\left(4:2\right)\right)\right)\\2^3+\sqrt{4}+2\left(1+3-4:2\right)\\8+2+4\\14$

Explicação passo a passo:

$2^3+\left(\sqrt{4}+2\left(1+3-\left(\frac{4}{2}\right)\right)\right)\\\mathrm{Aplique\:a\:regra}:\quad \:a+\left(b+c\right)=a+b+c\\2^3+\left(\sqrt{4}+2\left(1+3-\left(\frac{4}{2}\right)\right)\right)=2^3+\sqrt{4}+2\left(1+3-\left(\frac{4}{2}\right)\right)\\2^3+\sqrt{4}+2\left(1+3-\frac{4}{2}\right)\\2x^{3} =8\\\sqrt{4} =2\\2\left(1+3-\left(\frac{4}{2}\right)\right)=4\\\mathrm{Somar:}\:8+2+4=14$