Question

EQUAÇAO SEGUNDO GRAU
x²+20x-21=0

Answer 1

x2+20x-21=0

a) 1
b) 20
c) -21

∆= b²-4.a.c
∆= 20²-4.1.(-21)
∆= 400+84
∆= 484

x= -x±√∆/2.a
x= -20±√484/2.1
X= -20±22/2
x1= -20+22/2= 2/2= 1
x2= -20-22/2= -42/2= -21



Espero ter ajudado! ;)