• Matéria: Matemática
  • Autor: souz4m
  • Perguntado 3 anos atrás


 \frac{2}{3} -  \frac{1}{6}
 \frac{4}{5}  +  \frac{3}{10}
 \frac{ - 5}{ 6}  \frac{ - 7}{4}
 \frac{ - 3}{8}  +   \frac{1}{8}  +  \frac{5}{8}
 \frac{5}{6}  -  \frac{1}{5}
 \frac{ - 5}{9} -  \frac{1}{15}
 \frac{3}{4}  - 3
5 -  \frac{8}{3}

Respostas

respondido por: natoliveira8
1

Explicação passo-a-passo:

 \frac{2}{3}  -  \frac{1}{6}  =  \frac{(2 \times 2) - 1}{6}  =  \frac{4 - 1}{6}  =  \frac{3}{6}  =  \frac{1}{2}  \\  \\  \frac{4}{5}  +  \frac{3}{10}  =  \frac{(2 \times 4) + 3}{10}  =  \frac{8 + 3}{10}  =  \frac{11}{10}  \\  \\  \frac{ - 5}{6}  -  \frac{7}{4}  =  \frac{ - (2 \times 5) - (3 \times 7)}{12}  =  \frac{ - 10 - 21}{12}  =  -  \frac{31}{10}  \\  \\  \frac{ - 3}{8}  +  \frac{1}{8}  +  \frac{5}{8}  =  \frac{ - 3 + 6}{8}  =  \frac{3}{8}  \\  \\  \frac{5}{6}  -  \frac{1}{5}  =  \frac{(5 \times 5) - (6 \times 1)}{6 \times 5}  =  \frac{25 - 6}{30}  =  \frac{19}{30}  \\  \\  \frac{ - 5}{9}  -  \frac{1}{15}  =  \frac{ - (5 \times 5) - (3 \times 1)}{45}  =  \frac{ - 25 - 3}{45}  =  -  \frac{28}{45}  \\  \\  \frac{3}{4}  - 3 =  \frac{3 - (4 \times 3)}{4}  =  \frac{3 - 12}{4}  =  -  \frac{9}{4}  \\  \\ 5 -  \frac{8}{3}  =  \frac{(3 \times 5) - 8}{3}  =  \frac{15 - 8}{3}  =  \frac{7}{3}

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