Question

Sendo f(x,y,z) = xcos(y)+z, as derivadas parciais de f(x,y,z) são:

Answer 1

$f(x,y,z)=x*cos(y)+z\\\\ \frac{\partial f}{\partial x} =1*cos(y)+0 = cos(y)\\\\ \frac{\partial f}{\partial y} =x*-sen(y)+0 = -x*sen(y)\\\\ \frac{\partial f}{\partial z} =0+1 = 1$