Question

Exercícios

1) Resolva as equações do 2º grau completas utilizando Bhaskara.

a) x²-5x+6= 0
b) x²-8x+12=0
c) x²+2x-8= 0
d) x²-5x+8=0
e) x²-8x+8=0
f) x²-4x-5= 0
g) -x²+x+12= 0
h) x²+3x-4= 0​

Answer 1

Explicação passo-a-passo:

a)

x²-5x+6=0

a=1, b=-5, c=6

∆=(-5)²-4.1.6

∆=25-24

∆=1

x'=-(-5)+√1/2.1=5+1/2=6/2=3

x"=-(-5)-√1/2.1=5-1/2=4/2=2

b)

x²-8x+12=0

a=1, b=-8, c=12

∆=(-8)²-4.1.12

∆=64-48

∆=16

x'=-(-8)+√16/2.1=8+4/2=12/2=6

x"=-(-8)-√16/2.1=8-4/2=4/2=2

c)

x²+2x-8=0

a=1, b=2, c=-8

∆=(-2)²-4.1.(-8)

=4+32

=36

x'=-2+√36/2.1=-2+6/2=4/2=2

x"=-2-6/2=-8/2=-4

d)

x²-5x+8=0

∆=(-5)²-4.1.8

∆=25-32

∆=-7

S=∅

e)

2x²-8x+8=0

∆=(-8)²-4.2.8

∆=64-64

∆=0

x=-(-8)+√0/2.2=8/4=2

f)

x²-4x-5=0

∆=(-4)²-4.1.(-5)

∆=16+20

∆=36

x'=-(-4)+√36/2.1=4+6/2=10/2=5

x"=4-6/2=-2/2=-1

g)

-x²+x+12=0

∆=1²-4.(-1).12

∆=1+48

∆=49

x'=-1+√49/2.(-1)=-1+7/-2=6/-2=-3

x"=-1-7/-2=-8/-2=4

h)

x²+3x-4=0

∆=3²-4.1.(-4)

∆=9+16

∆=25

x'=-3+√25/2.1=-3+5/2=2/2=1

x"=-3-5/2=-8/2=-4